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Re: Passing multiple flags in a single {} replacement
From: |
Ole Tange |
Subject: |
Re: Passing multiple flags in a single {} replacement |
Date: |
Mon, 14 May 2012 13:49:16 +0200 |
On Sun, May 13, 2012 at 5:48 PM, Alastair Andrew <a.andrew@strath.ac.uk> wrote:
> If you call it with the -d flag it'll run parallel in --dry-run mode echo-ing
> its proposed runs allowing you to see the addition backslashes in the
> generated arguments. Using --nice inflates the number backslashes too.
The problem you are experiencing can be summed up as:
parallel -v ls ::: "-l -a"
Your problem is that you want the arguments to be parsed by the shell
and not escaped. That is in contrast to this situation:
parallel -v ls ::: "my file"
where you do _not_ want the argument to be parsed by the shell, but
want it escaped so it is interpreted as a single argument.
What you are hitting is therefore a design decision which makes sense
most of the time, but not all the time.
So what to do? One solution is to give the command line to 'bash -c':
parallel -v bash -c ls ::: "-l -a"
by doing so you can have your cake and eat it, too, so commands like
this will be possible:
parallel -v touch {1}\; bash -c ls {2} ::: "my file" ::: "-l -a"
Here the first part is quoted and the second part unquoted (by bash
-c). It also does the right thing with --nice.
/Ole